Question

When the momentum of body increases by 10% its k.E. Increase by?

Answer 1

K.E =P^2/2m

P'= 10/100+P
p'=0.1+P
P'=1.1 P
K.E'=P'^2/2m
K.E'=1.1P^2/2m

K.E'/K.E = P'^2/2m /P^2/2m

K.E'/K.E= 1.1 P^2/2m ×2m/P^2

cancel 2m with 2m and P^2 with P^2

K.E'/K.E = 1.21

K.E'= 1.21 K.E