Question

when the polynomial 2x cube - 3x square + 2x - 4 is divided to(x-2) , remainder is

Answer 1

Step-by-step explanation:

X - 2 = 0

X = 2

substitute the value of x in the polynomial

2 (2 x 2 x 2)-3(2 x 2)+2 x 2 - 4

2 x 8 - 3 x 4 + 4 - 4

16 - 12 + 4 - 4

4 is the remainder

Answer 2

Given,

• The polynomial $2x^3 -3x^2 + 2x -4$ is given.
• The divisor $x-2$ is given.

To find,

• Remainder when the polynomial $2x^3 -3x^2 + 2x -4$ is divided by $x-2$.

Solution,

When the polynomial $2x^3 -3x^2 + 2x -4$ is divided by $x-2$, the remainder is 4.

We can simply find the remainder by substituting the value of x = 2 in the given polynomial, we get

       p(x) = $2x^3 -3x^2 + 2x -4$

       p(2) = 2(2)³ - 3(2)² + 2(2) - 4

               = 16 - 12 + 4-4

               = 4

∴ The remainder is 4.

Hence, when the polynomial $2x^3 -3x^2 + 2x -4$ is divided by $x-2$, the remainder is 4.