Question

When the pressure of 5L of N2 is doubled and its temperature is raised from 300 K to 600 K , the final value of the gas would be?

Answer 1

I hope ryt my ans.........

Answer 2

Answer : The final volume of gas is 5 L.

Solution : Given,

Initial volume = 5 L

Initial temperature = 300 K

Final temperature = 600 K

Let, Initial pressure = x

Final pressure = 2x   ( as per question)

Using combined gas law,

$\frac{PV}{T}=constant$

Formula for two gases,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure

$P_2$ = final pressure

$V_1$ = initial volume

$V_2$ = final volume

$T_1$ = initial temperature

$T_2$ = final temperature

Now put all the given values in this formula, we get

$\frac{(x)\times 5L}{300K}=\frac{(2x)\times V_2}{600K}$

By rearranging the terms, we get the final volume of gas.

$V_2=5L$

Therefore, the final volume of gas is 5 L.