Question

When three resistors each having resistance are connected in parallel, their effective resistance is 3 ohm if this three resistances are connected is series, the total effective resistance will be
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Answer 1

Answer:R/3=3

R=3×3=9

3R=27ohms

Explanation:

Answer 2

Answer:

1/Rp =1/3 = 1/R1+ 1/R2+ 1/R3

Let the unknown resistance be x

1/x + 1/x + 1/x = 1/3

3/x = 1/3

x = 9

Now in series,

R = x + x + x

= 9 + 9 + 9

= 27 (ohms)