Question

When two bodies approach each other uniformly the distance between them decreases by 32m for every 20s.If they move in the same direction ,Distance between them increases by 6m for every 10s.Find the velocities of the two bodies?

Answer 1

Answer:

0.5m/s

Explanation:

in opposite directions

v1+v2=32/20m/s=8/5m/s

in same directions

V1-V2=3/5m/s

Then by solving the two equations

2V1=22/10=>V1=1.1m/s

V1-V2=0.6=>V2=V1-0.6

V2=0.5m/s

Answer 2

Given,

Distance between two bodies decreases by 32m for every 20s

In the same direction distance between them increases by 6m in 1`0s

To Find,

Velocities of two bodies.

Solution,
At first two bodies are moving in opposite direction

So their velocities V1 and V2 ,

V1+V2=32/20=1.6m/s

So, V1+V2=1.6---(1)

Then two bodies are in same3 direction.

So their velocities V1 and V2,

V1-V2=6/10=0.6m/s---(2)

BY adding equation 1 and equation 2 we get,

2V1=2.2m/s
⇒V1=1.1m/s

Putting the value of V1 in equation,

1.1+V2=1.6

⇒V2=0.5m/s

Hence, velocities of the two bodies are 1.1 m/s and 0.5m/s.