Question

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?
Individual Question

4

14

16

20

50

Answer 1

$Your \: answer$

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Put the given values of x and y !

${3x}^{2} - 2y = 0 \\ 3{(3)}^{2} - 2 ( 5 ) \\ 3 ( 9 ) - 10 \\ 27 - 10 \\ 17 \\ \\ {2x}^{2} - 3y = 0 \\ {2 (3)}^{2} - 3 ( 5 ) \\ 2 ( 9 ) - 15 \\ 18 - 15 \\ 3 \\ Hence 17 - 13 = 4$

Answer 2

here x=3,and y=5
,from 1st equation ,
this implies that

3(3^2)-2(5)=27-10=17
put the value of x,and y
in equation second,
we get ,
2(3^2)-3(5)
=18-15
=3


and 17-3=14
hence the equation first is exceeded by 14 than equation second .
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