when you apply a force F at the end of a wrench how much torque can it generate to open the nut ? assume that the force wrench and nut lie in the plane of the paper
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Given that we are applying a force of 5 N and a nut is opened by a wrench of length 10cm ( is also equal to 0.1 m). Moment of force is given by formula r×F.
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Given that we are applying a force of 5 N and a nut is opened by a wrench of length 10cm ( is also equal to 0.1 m). Moment of force is given by formula r×F. Hence 0.1×5=0.5N−m. Hence moment of force is 0.5Nm.
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