when you mix solutions of lead (II) nitrate and potassium iodide
i) wht is the color of the precipitate formed. Name the compound formed.
ii) balanced chemical equation.
iii) is this double displacement reaction??
Urgent answer needed :-)
Answers
Answered by
699
Hi there !!
Lead nitrate = Pb[NO]₂
Potassium Iodide = KI
Colour of the precipitate formed is Yellow [ Lead Iodide ]
KI + Pb[NO₃]₂ -----> KNO₃ + PbI₂
-----> UNBALANCED EQUATION
2Kl+ Pb[NO₃]₂ -----> 2KNO₃ + PbI₂
----> BALANCED EQUATION
This is an example of double displacement reaction.
Also , as yellow precipitate is formed , this is also an example of precipitation reaction
Lead nitrate = Pb[NO]₂
Potassium Iodide = KI
Colour of the precipitate formed is Yellow [ Lead Iodide ]
KI + Pb[NO₃]₂ -----> KNO₃ + PbI₂
-----> UNBALANCED EQUATION
2Kl+ Pb[NO₃]₂ -----> 2KNO₃ + PbI₂
----> BALANCED EQUATION
This is an example of double displacement reaction.
Also , as yellow precipitate is formed , this is also an example of precipitation reaction
wanderlust1301:
hey plz answer my other questions as well
Answered by
217
The colour of precipitate is yellow. Compound- lead iodine ( PbI2)
It is double displacement reaction
Pb(NO3)2 + 2KI = PbI2 + 2KNO3
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