Question

Which are the zeroes of p(x) = x2

– 1:

(a) 1, –1
(b) – 1, 2
(c) –2, 2
(d) –3, 3

explain ????????????????​

Answer 1

Hey there

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Question - Which are the zeroes of p(x) = x2

– 1:

(a) 1, –1

(b) – 1, 2

(c) –2, 2

(d) –3, 3

Answer -

In such polynomials where the middle term is not given they are very easy to solve

${x}^{2} - 1 = 0$

Then

${x}^{2} = 1$

The

$x = \sqrt{1}$

From here two value comes as it is a quadratic equation

That are +1 and - 1

Hope it helped you

Answer 2

Answer:

hey mate here's ur answer

Step-by-step explanation:

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