Question

Which are the zeroes of p(x) = x² + 7x + 12 :

(a) 4, –3 (b) –4, 3 (c) –4, –3 ​

Answer 1

Answer:

c) option is correct

Step-by-step explanation:

apply hit and trial method

p(-4)=0 &p(-3) is also 0

Answer 2

Answer:

Option (c)

Step-by-step explanation:

x² + 7x + 12 = 0

x² + 3x + 4x + 12 = 0

x(x+3) + 4(x+3) = 0

(x+3)(x+4) = 0

x= -3 and x= -4

Hence, option (c) is the correct answer.

Hope it helps you!