Question

which is the magnetic momentum of cuprous chloride on of the basis of axial rotation​

Answer 1

answer : option (B)

explanation : Cuprous chloride, CuCl [Cu+ ]

number of electrons present in Cu+ = 28

so, electronic configuration of $Cu^+$ : 1s², 2s², $2p^6$, 3s², $3p^6$, $4s^0$, $3d^{10}$.

here, it is clearly shown that, number of unpaired electrons in Cu+ , n = 0.

so, magnetic moment, $\mu=\sqrt{n(n+2)}$ = 0

hence, magnetic moment of cuprous chloride on the basis of axial rotation is 0.0BM.

Answer 2

Option (B) : 0.0B.M.

Is the answer.