Question

Which is the most suitable reagent among the
following to distinguish compound (3) from rest
of the compounds ?
1. CH₃ -C ≡ C-CH₃
2. CH₃ -CH₂ -CH₂ -CH₃
3. CH₃ -CH₂C ≡ CH
4. CH₃ -CH = CH₂.
(a) Bromine in carbon tetrachloride
(b) Bromine in acetic acid
(c) Alk KMnO₄
(d) Ammonical silver nitrate.

Answer 1

Answer:

a bromine in carbon in acid

Answer 2

(d) Ammonical silver nitrate

Explanation:

Compound 3 (CH3-CH2C=CH) possesses a terminal alkyne. This alkyne reacts with ammoniacal silver nitrate, while compounds 1, 2 and 4 do not react with ammoniacal silver nitrate. So we can use this chemical property to distinguish Compound 3 from the rest of the compounds.  

Option D is the answer.