Question

Which linear function represents the line given by the point-slope equation y + 7 = –y plus 7 equals negative StartFraction 2 Over 3 EndFraction left-parenthesis x plus 6 right-parenthesis.(x + 6)? f(x) = –f(x) equals negative StartFraction 2 Over 3 EndFraction x minus 11.x – 11 f(x) = –f(x) equals negative StartFraction 2 Over 3 EndFraction x minus 1.x – 1 f(x) = –f(x) equals negative StartFraction 2 Over 3 EndFraction x plus 3.x + 3 f(x) = –f(x) equals negative StartFraction 2 Over 3 EndFraction x plus 13.x + 13

Answer 1

Answer:

$f(x)=-\frac{2}{3}x-11$

Step-by-step explanation:

Here, the given equation of line,

$y+7=-\frac{2}{3}(x+6)$

By distributive property,

$y+7=-\frac{2}{3}(x)-\frac{2}{3}(6)$

$y+7 = -\frac{2}{3}x - 4$

Subtraction property of equality,

$y=-\frac{2}{3}x -4 - 7$

$y=-\frac{2}{3}x-11$

Replace y by f(x),

$f(x) = -\frac{2}{3}x - 11$

Which is the required linear function

Answer 2

Given : line given by the point-slope equation y + 7 = -(2/3)(x + 6)

To Find : Which linear function represents the line

f(x) =  (-2/3)x - 11

f(x) =  (-2/3)x - 1

f(x) =  (-2/3)x  +3

f(x) =  (-2/3)x  +13

Solution:

y + 7 = -(2/3)(x + 6)

=> y + 7 = -2x/3  - (2/3)6

=>  y + 7 = -2x/3  - 4

=>  y  = -2x/3  - 11

=> y = (-2/3)x - 11

f(x) = y

=> f(x)  = (-2/3)x - 11

f(x)  = (-2/3)x - 11 is linear function represents the line given by the point-slope equation y + 7 = -(2/3)(x + 6)  

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