Question

Which of the following are the factors of 81n^4 - 625?
(1) (9n^2 +25) (9n^2 + 25)
(2) (9n^2 + 25) (3n^2-5) (3n^2 +5)
(3) (9n^2 + 25) (31 +5) (3n-5) (4) (9n^2 - 25) (9n^2 - 25)​

Answer 1

Answer:

$(3n-5)(3n+5)(9n^{2}+25)$

Step-by-step explanation:

$81n^{4}-625$

$(9n^{2})^{2}-25^{2}$

$a^{2}-b^{2}$

$(9n^{2}-25)(9n^{2}+25)$

$a^{2}-b^{2}$

$(3n-5)(3n+5)(9n^{2}+25)$