Which of the following arguments are correct and which are not correct? Give reasons.
i) If two coins are tossed simultaneously there are three possible outcomes - two heads,two tails or one of each. Therefore, for each of these outcomes, the probability is 1/3.
ii) If a die is thrown, there are two possible outcomes - an odd number or an even number. Therefore, the probability of getting an odd number is 1/2.
Answers
Answered by
7
both the arguments are right.
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Answered by
23
I &II are true
if two coins are simultaneously possible are{HH,TT,HT,TH}
P(H)=1/3
P(T)=1/3
II) if die is thrown possibles are{1,2,3,4,5,6}
odd number possible is {1,3,5}
even number possible is {2,4,6}
then,
P(E)=3/6=1/3
P(O)=3/6=1/3
probability = no. of possible occurrence of an event /total no. of out comes
P(E)+P(Ebar)=1
OK.
if two coins are simultaneously possible are{HH,TT,HT,TH}
P(H)=1/3
P(T)=1/3
II) if die is thrown possibles are{1,2,3,4,5,6}
odd number possible is {1,3,5}
even number possible is {2,4,6}
then,
P(E)=3/6=1/3
P(O)=3/6=1/3
probability = no. of possible occurrence of an event /total no. of out comes
P(E)+P(Ebar)=1
OK.
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