which of the following combination of volumes(ml) of c2h4(g) and o2 (g)respectively is required obtain 400ml of co2 (g)?all volumes are measured at sTp
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Answer:
C2H4(g)+3O2(g)=2CO2(g)+2H2O
From Gay lussac's law or law of gasseous volume
Ratio of volumes =1:3:2
Given:
400ml of CO2=2×200ml
C2H4=1×200 =200ml4
O2=3×200 =600ml
Explanation:
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