Chemistry, asked by rasheedpokkath6415, 1 year ago

Which of the following complex ion does not possess tetrahedral shape?Select the proper choice from the given choices.(A) [MnO₄]⁻ (B) [Ni(CO)₄](C) [Ni(CN)₄]²⁻ (D) [Cu(NH₃)₄]²⁺

Answers

Answered by patelaayushi2624
2

Answer:

[Ni(CN)4]^2-

Explanation:

Here it is dsp2 and does not possess tetrahedral shape.

Answered by tushargupta0691
0

Answer:

Tetra- signifies four, and -hedral implies the face of a solid; "tetrahedral" literally means "having four faces." This shape is produced when there are four bonds all on one central atom and no lone electron pairs. According to the VSEPR theory, the bond angles between the electron bonds are 109.5°..

Explanation:

(A) [MnO₄]⁻

  • Manganese (Mn) is in a +7 oxidation state.
  • Its electronic configuration is 3d⁰ 4s⁰.
  • It shows charge transfer spectra.
  • It also possesses sp³ hybridization.

(B) [Ni(CO)₄]

  • Nickel (Ni) is in a zero oxidation state.
  • Its electronic configuration is 3d⁸ 4s².
  • All the electrons are paired in the five d-orbitals so it is a diamagnetic complex.
  • Thus it has sp³ hybridization.

(C) [Ni(CN)₄]²⁻

  • Nickel (Ni) is in a +2 oxidation state.
  • Its electronic configuration is 3d⁸ 4s⁰.
  • All the electrons are paired in the four d-orbitals so it is a diamagnetic complex.
  • Thus it has dsp² hybridization.

(D) [Cu(NH₃)₄]²⁺

  • Copper (Cu) is in a +2 oxidation state.
  • Its electronic configuration is 3d⁹ 4s⁰.
  • All the electrons are paired in the four d-orbitals except one which occupies the fifth d-orbital.
  • Thus it has sp³ hybridization.

Hence, the complex ion that does not possess a tetrahedral shape is (C) [Ni(CN)₄]²⁻.

The correct option is (C) [Ni(CN)₄]²⁻.

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