Question

Which of the following complex ion is not expected to absorb
visible light ?
(a) [Ni(CN)₄]²⁻
(b) [Cr(NH₃)₆]³⁺
(c) [Fe(H₂O)₆]²⁺
(d) [Ni(H₂O)₆]²⁺

Answer 1

Answer:

option (a) is the correct answer

Answer 2

Tetracyanonickelate or [Ni(CN)₄]²⁻ is the complex which can't absorb visible light.

Explanation:

• Nickel is a transitional metal with atomic number 28.

• This nickel in the complex tetracyanonickelate is of charge +2.

• So nickel is having an electronic configuration of [Ar] 3d8 4s0.

• So here the d orbital has got 8 electrons.

• In absence of any the nickel ion can absorb the visible light.

• But cyanide being a strong field , pairs up the electrons to form the coordinate covalent bonds there.

• So the cyanide makes the nickel ion have no unpaired electron, hence no colour.

For more information about tetracyanonickelates,

https://brainly.in/question/6093018

Which complex has square planar structure?

a) [Ni(CO)₄]b) [NiCl₄]²⁻c) [Ni(CN)₄]²⁻d) Fe(CO)₅]

https://brainly.in/question/15420197

The hybridization involved in complex [Ni(CN)₄]²⁻ is

(At. No. Ni = 28) [2015 RS]

(a) dsp² (b) sp³

(c) d²sp² (d) d²sp³