Which of the following constants can be added to x 2 - x to form a perfect square trinomial? 1
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Answered by
5
Given Equation is x^2 - x.
(1) Now, Take the middle term i.e 1.
(2) Divide it by 2
(3) Then Square it.
Now,
= > x^2 - x + (1/2)^2
= > x^2 - x + 1/4.
= > (x - 1/2)^2
Therefore the constant that can be added is (1/4).
Hope this helps!
(1) Now, Take the middle term i.e 1.
(2) Divide it by 2
(3) Then Square it.
Now,
= > x^2 - x + (1/2)^2
= > x^2 - x + 1/4.
= > (x - 1/2)^2
Therefore the constant that can be added is (1/4).
Hope this helps!
siddhartharao77:
:-)
Answered by
0
Answer:
1/4
Step-by-step explanation:
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