Question

which of the following element would lose an electron easily Na, Mg, K, F​

Answer 1

Answer:

Which of the elements will loose electrons easily…

Explanation:

Loosing electrons is only possible for any element if it has least number of electrons present in its outer most orbit.

Now lets look at the elements that you have given…

K (potassium) its electron valency is 1 so only 1 electron is present in the outer most orbit.

Ca (calcium) it has 2 electrons present in the outermost orbit.

Na (sodium) its electronic valency is 1.

Mg (magnesium) its valency is 2.

Now comparing the above mentioned valencies, Na has least likely to loose its electron as compared to potassium.

So the correct answer is K (potassium).

Answer 2

Na - Sodium :

●The atomic number of sodium is 11.

●The electronic configuration of sodium is 1s^2 2s^2 2p^6 3s^1.

●So the valency of sodium is 1. It lose 1 electron to attain octet.

Mg - Magnesium:

● The atomic number of magnesium is 12.

● The electronic configuration of magnesium is 1s^2 2s^2 2p^6 3s^2.

●So the valency of magnesium is 2. It lose 2 electrons to attain octet.

K - potassium:

● The atomic number of potassium is 19.

●The electronic configuration of potassium is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^1.

●So the valency of potassium is 1. It lose 1 electronic to attain octet.

F - Fluorine:

● The atomic number of fluorine is 9.

● The electronic configuration of fluorine is 1s^2 2s^2 2p^5.

●So the valency of fluorine is 7.It lose 7 electrons to attain octet.

By comparing..

The potassium would lose an electron easily,when compared to sodium and other.