Question

Which of the following is most powerful to coagulate the
negative colloid?
(a) ZnSO₄ (b) Na₃PO₄
(c) AlCl₃ (d) K₄[Fe(CN)₆]

Answer 1

Answer:

C. AlCl₃

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Answer 2

"Option d)" is the most effective coagulating active ion.

Explanation:

The colloidal particles in ferric hydroxide having a positive charge particle. The ferric hydroxide is positively charged.

Applying Hardy Schulze rule:

The active ion for the coagulation of the ferric hydroxide solution must be negatively (- ve) charged and highest the negative charge of the active ion, most effective coagulating active ion.  

$K_3[Fe(CN)_6]$ → $3K^+$  + $[Fe(CN)_6]^{3-}$

and this coordination species has highest negative charge.  

Thus, option d) is the most effective coagulating active ion.