Physics, asked by BrainlyHelper, 11 months ago

Which of the following relationships between the acceleration a and the displacement x of a particle involve simple harmonic motion?a. a = 0.7 xb. a = -200 x²c. a = -10 xd. a = 100 x³

Answers

Answered by abhi178
0
When a particle moves to and fro along a line, the motion is called simple harmonic motion. in simple harmonic motion, direction of acceleration is just opposite to direction of its motion.
e.g., condition of simple harmonic motion : a=-\omega^2x
where a is acceleration, \omega is angular frequency and x is the displacement of particle in simple harmonic motion.

here, option (c), a = -10x is similar to a = \omega^2x
where \omega^2=10
e.g., angular frequency or angular velocity = √10 rad/s

hence, option (c) is correct answer.
Answered by anjali626133
2

Answer:

......................................................

Similar questions