Which of these can be the sum of three consecutive natural
numbers?
a. 55
b. 56
c. 57
d. 58
justice2:
57
its 57
oo
when we consider three consecutive numbers n-1, n, n+1.... adding all the three gives u 3n... so the point is sum of any three consecutive numbers is a multiple of 3
and the only option satisfying this is 57!!
hope it helps u
Answers
Answered by
10
Hi ,
Sum of three consecutive numbers
is always divisible by 3 .
Therefore ,
According to the options given ,
57 is the only number which divisible
by 3 .
Option ( C ) is correct.
Verification :
Let x , ( x + 1 ) , ( x + 2 ) are three
consecutive numbers ,
x + x + 1 + x + 2 = 57
3x + 3 = 57
3x = 57 - 3
3x = 54
x = 54/3
x = 18
Therefore ,
Required numbers are 18 , 19 , 20
I hope this helps you.
:)
Sum of three consecutive numbers
is always divisible by 3 .
Therefore ,
According to the options given ,
57 is the only number which divisible
by 3 .
Option ( C ) is correct.
Verification :
Let x , ( x + 1 ) , ( x + 2 ) are three
consecutive numbers ,
x + x + 1 + x + 2 = 57
3x + 3 = 57
3x = 57 - 3
3x = 54
x = 54/3
x = 18
Therefore ,
Required numbers are 18 , 19 , 20
I hope this helps you.
:)
thanks
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