Question

Which one of the following is the zero of p(x)= 1x+m:-
(a) m/1
(b) 1/m
(c) -m/1
(d) -m/1
(Solve step by step solution)
Class 9th ​

Answer 1

Answer:

m/1 is the correct one

Step-by-step explanation:

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Answer 2

Answer:

―m/1

Step-by-step explanation:

As per the the provided information in the given question, we have been given a polynomial that is p(x) = 1x + m. We're asked to calculate the zero of the p(x).

Zero of the polynomial is a number [x] at which the whole polynomial becomes 0. So, in order to calculate the zero of p(x) , we have to solve to equation p(x) = 0.

$\implies \sf { p(x) = 0 }$

According to the question, the value of p(x)is 1x + m. Substitute the value.

$\implies \sf {1x + m = 0 }$

Now, we have to use transposition method to find the value of x. In transposition method, we transpose the terms from LHS to RHS and vice versa and by changing the arithmetic operations when transposed. Here m 's arithmetic operator is + so it'll become - m in RHS.

$\implies \sf {1x = 0 - m}$

Performing subtraction in RHS.

$\implies \sf {1x = - m}$

Transposing 1 from LHS to RHS. Here, 1 is in the form of division in LHS so it'll become in the form of multiplication in RHS.

$\implies \boxed{ \sf {\red{x = \dfrac{ - m}{1} }}}$

Therefore, the zero of p(x) is -m/1.

$\rule{200}2$