Question

which quantum number are obtained from hydrogen atom schoodinger's wave equation ​

Answer 1

Answer:

three quantum numbers

Schrödinger's approach requires three quantum numbers (n, l, and ml) to specify a wavefunction for the electron.

Explanation:

hope it helps you

Answer 2

For the electrons wave equation to be specified using Schrödinger's method, three quantum numbers, n, l, and $m_{l}$, are needed.

The quantum statistics disclose details about an electron's spatial dispersion. While n may be any positive number, only particular l and $m_{l}$ numbers are permitted for just a known amount of n.

The primary quantum number (n)

• The primary quantum number (n) is one of the 3 quantum numbers which indicate an electron's overall average position from of the nucleus. 
• n=1,2,3,4 signifies the energy of a particle as well as the distance of the an electron from of the nuclei

The Azimuthal Quantum Number (l)

• The azimuthal quantum number is another name for the 2nd quantum number (l).
• One among 3 quantum numbers which characterise the geometry of an atom's area of space.
• The l value describes the form of the atom's area of space.
• The permissible values of l are influenced by the sum of n and range from zero to n 1:

l=0,1,.,2,3,..(n−1)

The Quantum Magnetic Number $m_{l}$

• The magnetic component is the third quantum number ($m_{l}$). One of 3 quantum numbers that characterise the direction of an electron's space area with regard to a magnetisation.
• The quantity of ml specifies the direction of an atom's area in space with regard to a magnetisation.
• The permitted values of ml are set by the value of l: $m_{l}$ may range between l and l in integer steps:

m=−l,−l+1,...0,...l−1,l

SPJ2