Which term of ap 5 15 25 will be 130 more than 31st term
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Answer:
44th term
Step-by-step explanation:
We have the given AP 5, 15, 25 ......
Here, first term-a=5 ,common difference-d=10
Let an be 130 more than a31
Thus ,
⇒an-a31 =130
⇒{a+(n-1)d}-{a+30d}=130
⇒5 +nd-d -5-30d =130
⇒nd-31d =130
⇒(n-31)d=130
⇒n-31 (10)=130
⇒n-31 =130/10
⇒n-31 =14
⇒n=14+31
⇒n=44
44th term of AP will be 130 more than 31st term.
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