which term of the A .P :121,117,113, ...... is its first nagative term
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Given first term = 121
Common difference = 117 - 121 = -4 .
Divide the first term by common difference; a/d = 121/4 = 30....
Finding the 31th term = 121+ 30(-4) = 121-120 = 1 .
Now The 32nd term of the A. P = 121+31(-4) = 121-124=-3 .
The 32 nd term of A. P is the first negative term of the A. P
Common difference = 117 - 121 = -4 .
Divide the first term by common difference; a/d = 121/4 = 30....
Finding the 31th term = 121+ 30(-4) = 121-120 = 1 .
Now The 32nd term of the A. P = 121+31(-4) = 121-124=-3 .
The 32 nd term of A. P is the first negative term of the A. P
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