Which term of the AP :3,8,13,18........is 78
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Step-by-step explanation:
16th term
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First term of AP = a = 3
Common difference = d = Second term - First term
= 8 - 3
= 5
Last term = an ( please note that it is that n is written down right in small font of letter a ) = 78
last term = first term + (number of terms - 1) common difference
Let n be the number of terms
an = a + (n-1)d
78 = 3 + (n-1) 5
78 - 3 = 5n - 5
75 + 5 = 5n
80 = 5n
n = 80/5 = 16
=> The 16th term of the AP is 78
Please mark this answer as brainliest
Common difference = d = Second term - First term
= 8 - 3
= 5
Last term = an ( please note that it is that n is written down right in small font of letter a ) = 78
last term = first term + (number of terms - 1) common difference
Let n be the number of terms
an = a + (n-1)d
78 = 3 + (n-1) 5
78 - 3 = 5n - 5
75 + 5 = 5n
80 = 5n
n = 80/5 = 16
=> The 16th term of the AP is 78
Please mark this answer as brainliest
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