Question

which term of the AP 63,65,67,... and 3,10,17,... are equal ?

Answer 1

Let the first term of first AP be a1 and difference be d1.

Let the second term of first AP be a2 and difference be d2.

a1=63

d1=65-63=2

a2=3

d2=10-3

=7

Now let the term which is equal be n.

a1+(n-1)d1=a2+(n-1)d2

=63+(n-1)(2)=3+(n-1)(7)

=63+2n-2=3+7n-7

=2n+61=7n-4

5n=65

n=65/5

=13

13th term is equal

It is a+(13-1)d

=a+12d

=3+12*7

=3+84

=87

87 is the term that is equal.It is the 13th term.

Hope it helps.