Which term of the ap5,15,25,..... Will be 130 more than its 31st term?
Answers
Answered by
7
Hey user !!
Here's the answer you are looking for
In this AP,
a = 5
d = 25 - 15 = 15 - 5 = 10
Let the term that is 130 more than the 31st term be nth term.
So,
nth term = 31st term + 130
a + (n - 1)d = a + (31 - 1) d + 130
(n - 1)d = 30×10 + 130 = 430
(n - 1)10 = 430
(n - 1) = 43
n = 44 (ans.)
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
In this AP,
a = 5
d = 25 - 15 = 15 - 5 = 10
Let the term that is 130 more than the 31st term be nth term.
So,
nth term = 31st term + 130
a + (n - 1)d = a + (31 - 1) d + 130
(n - 1)d = 30×10 + 130 = 430
(n - 1)10 = 430
(n - 1) = 43
n = 44 (ans.)
★★ HOPE THAT HELPS ☺️ ★★
Similar questions