Math, asked by harshgaur, 1 year ago

Which term of the ap5,15,25,..... Will be 130 more than its 31st term?

Answers

Answered by AR17
7
Hey user !!

Here's the answer you are looking for

In this AP,

a = 5

d = 25 - 15 = 15 - 5 = 10

Let the term that is 130 more than the 31st term be nth term.

So,

nth term = 31st term + 130

a + (n - 1)d = a + (31 - 1) d + 130

(n - 1)d = 30×10 + 130 = 430

(n - 1)10 = 430

(n - 1) = 43

n = 44 (ans.)



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