Question

Why is there no ring expansion when hcl is added to a compound?

Answer 1

hey dude

The Beckmann rearrangement, named after the German chemist Ernst Otto ... The Beckmann solution consists of acetic acid, hydrochloric acid and acetic anhydride, and was widely

Answer 2

Explanation:

[N.B. - the formulae are (C_4H_8C

4

H

8

) and not (CH), and (C_4H_1_0O ) instead of (CHO)]

As per the given formula, it can be inferred that the organic compound C_4H_8C

4

H

8

is 2-methylpropane, or Butene. When Butene reacts with hydrochloric acid, it results in the formation of

2-methyl-2-chloropropane.

The structural diagram has been attached below.

So, in the first case, we get 2-methyl-2-chloropropane after the completion of the reaction. In the next step, on hydrolysis with aqueous alkali, we get C_4H_1_0O , or 2-methyl-2-propanol.

Ans) A = 2-methylpropane

B = 2-methyl-2-chloropropane

C = 2-methyl-2-propanol