Chemistry, asked by rakhi37288, 1 year ago

Why ZnCl2 is used in the preparation of haloalkane by reaction of alcohols with halogen acids​

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Answered by madhusaraf45
1

Explanation:

Preparation of chloroalkane is an example of the reaction of an alcohol with halogen acid to form haloalkane. In this case, primary alcohol and secondary alcohol react with HCl acid gas to form haloalkane in the presence of anhydrous ZnCl2, which act as a catalyst in this reaction.

Or you can simply say........It happen so because Anhydrous ZnCl2,act as a catalyst in the reaction of the preparation of Chloroalkane

Answered by tejashwini5777
1

answer for your question

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