without actual calculation ,proof that (x-2) is a factor of the polynomial (3x³-13x²+8x+12). Also Factorise it completely
Answers
Answered by
3
we can factorise the whole term as follows:-
3x²(x-2)-7x(x-2)-6(x-2)
taking (x-2) common-
(x-2)(3x²-7x-6)
thus (x-2) is a factor of the given polynomial
hope this helps!
3x²(x-2)-7x(x-2)-6(x-2)
taking (x-2) common-
(x-2)(3x²-7x-6)
thus (x-2) is a factor of the given polynomial
hope this helps!
NilendraSinghTomar1:
wrong
then what's the answer?
is it correct?
I also don't know but it's wrong my maths teacher asked yesterday
to me
see this is the technique i use in my 12th maths! and if wanna confirm just multiply it and you will get your answer! and this method is allowed!
but you must know the answer
I m in 9
ok then it might not work in ur standard! cz this is bit tricky method which board doesnt allow in lower standard
what you can do is,you can divide (x-2) by the polynomial, if you get no remainder then it is proved!
Answered by
1
If k is a factor p (k) = 0
Similarly, if x - 2 is a factor
P (2) = 0
So 3 ×8 -13×4 +16+12 = 24 +28 - 52 = 0
Hence proved
X - 2 is a factor
Thank u★★★
#ckc
Similarly, if x - 2 is a factor
P (2) = 0
So 3 ×8 -13×4 +16+12 = 24 +28 - 52 = 0
Hence proved
X - 2 is a factor
Thank u★★★
#ckc
Thank u
welcome
plz solve my three questions also given in my question (2 one)
Where
after this question there is one more question of three sub parts
in my question
I can't see
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