Without actual division prove that 2x⁴-5x³+2x³-x+2is divisible by x²-3x+2
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x²-3x+2
=x²-2x-1x+2
=x(x-2)-1(x-2)
=(x-2)(x-1)
so that,,
(x-2)(x-1) are factors.
----> (x-2)
x-2=0
--> x=2
-->g(x)=2
g(x)=2x^4-5x^3+2x^2-x+2
g(2)=2(2)^4-5(2)^3+2(2)^2-2+2
=32-40+8
====>-40+40=0
so that (x-2) is a factor..
---> (x-1)
x-1=0
x=1
So,
g(x)=1
g(x)=2x^4-5x^3+2x^2-x+2
g(1)=2(1)^4-5(1)^3+2(1)^2-1+2
=2-5+2-1+2
=>>>6-6=0
(x-1) is also a factor!! :)
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