Without calculating the cubes find the value of (0.2)3-(0.3)3+(0.1)3
Answers
Answered by
4
We can use the following to evaluate this:
a^3 - b^3 - c^3 - 3abc = (a + b + c)( a^2 + b^2 + c^2 - ab - bc - ca)
a^3 - b^3 - c^3 = (a + b + c)( a^2 + b^2 + c^2 - ab - bc - ca) + 3abc
Hope this helps.
a^3 - b^3 - c^3 - 3abc = (a + b + c)( a^2 + b^2 + c^2 - ab - bc - ca)
a^3 - b^3 - c^3 = (a + b + c)( a^2 + b^2 + c^2 - ab - bc - ca) + 3abc
Hope this helps.
Similar questions
World Languages,
8 months ago
English,
8 months ago
English,
1 year ago
Physics,
1 year ago
English,
1 year ago