Question

without expanding show that the value of determinant is zero​

Answer 1

Answer:

Step-by-step explanation:

Let row1(R1)= R2 - R1

ie 1st term of R1 becomes

(x+2y)-(x+y)=y

So similarly R1➡ y y y

Next R3 becomes = R3 - R2

ie 1st term of R3 is (x+3y)-(x+2y)=y

So similarly R3 ➡y y y

Now the determinant is like

y y y

x+2y x+3y x+5y

y y y

Since 2 rows of a determinant are same its value is 0.