Math, asked by di5v5atojappu, 1 year ago

without using trignoetric table evaluate; (3 cos 43/sin 47)2- cos 37 * cosec 53 / tan 5* tan 25 * tan 45 *tan 65 * tan 85

Answers

Answered by ARoy
197
(3cos43°/sin47°)²-cos37°cosec53°/tan5°tan25°tan45°tan65°tan85°
={3cos(90°-47°)/sin47°}²-cos37°cosec(90°-37°)/tan5°tan25°×1×tan(90°-25°) tan(90°-5°)
=(3sin47°/sin47°)²-cos37°sec37°/tan5°tan25°cot25°cot5°
=9-1
=8

Answered by prajwalbarsagade358
89

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