write 2 log 3 - 3 log 2 as log N and find its value
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sunparhi bro am pro part
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Answer:
1)log 16-log 2 = log (16/2) = log 8
Here N = 8
2) 3 log 4 = log 4³ = log 64 Here N = 64
3) 2 log 3-3 log 2 = log 3²-log 2³ = log 9- log 8 = log (9/8)..Here N = 9/8
4) log 243 + log 1=log (243"1) = log 243
Here N = 243
5) log 10+ 2 log 3-log 2 = log 10+ log 3² - log 2
= log 10+ log 9 - log 2 = log (10*9) - log 2 = log 90-log 2 = log (90/2) = log 45....Here N = 4.
I hope it's helpful
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