Chemistry, asked by singhabhi8863, 1 year ago

Write 2 steps involved the extraction involved of mercury and impure of copper

Answers

Answered by royalboyayush
0

Oxidation is the reaction of rock minerals with oxygen, thus changing the mineral composition of the rock. When minerals in rock oxidize, they become less resistant to weathering. Iron, a commonly known mineral, becomes red or rust colored when oxidized.Oxidation is the reaction of rock minerals with oxygen, thus changing the mineral composition of the rock. When minerals in rock oxidize, they become less resistant to weathering. Iron, a commonly known mineral, becomes red or rust colored when oxidized.

Answered by MsAainaDz
0

Answer:

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For reflexive:-

if the relation is reflexive

then,(a,a) € R

i.e, 1 + a²>0

Since, square number is always positive

Hence, 1+a²>0 is true for all value of a.

So, the given relation is reflexive

For symmetric:-

To check whether symmetric or not,

if, (a,b)€ R, then (b,a)€ R

i.e, if 1+ab<0

then, 1+ba>0

since, if 1+ab>0, then 1 + ba>0

is always true for all value of a and b.

Hence, the given relation is symmetric.

For transitive:-

To check whether symmetric or not,

if, (a,b)€R and (b,c)€R, then (a,c)€R

i.e, if 1+ab>0 and 1+bc>0 then 1+ac>0

Lets, take an example

a= -8, b= -2 , c= 1/4

1+ab= 1+(-8)(-2)=1+16=17, { 17>0}

1+bc= 1+(-2)(1/4)=1-1/2=1/2, {1/2>0}

1+ac= 1+(-8)(1/4)=1-2= -1 ,{-1<0}

Since, 1+ac < 0

when, 1+ab>0 and 1+bc>0

•°• The condition is not true for all value of a,b and c

Hence, the given relation is not transitive.

Therefore, the relation is reflexive, symmetric but not transitive.

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