Math, asked by ajitparmar39, 11 months ago

Write 4 solutions for 2x + 3y = 8 !!​

Answers

Answered by readyplayerone
0

Answer:

1)if x=1y=2

2+6=8

2)ifx=2,y=1

4+3=7

3)if x=2,y=3

4+9=13

Answered by jitekumar4201
1

Answer:

1. x = 0 and y = \dfrac{8}{3}.

2. x = 1 and y = 2

3. x = \dfrac{5}{2} and y = 1

4. x = 4 and y = 0

Step-by-step explanation:

Given equation-

2x + 3y = 8

If x = 1 then

2(1) + 3y = 8

2 + 3y = 8

3y = 8 - 2

3y = 6

y = 2

Hence x = 1 and y = 2

If y = 1 then

2x + 3(1) = 8

2x + 3 = 8

2x = 8 - 3

2x = 5

x = \dfrac{5}{2}

Hence, x = \dfrac{5}{2} and y = 1

If x = 0 then

2(0) + 3y = 8

3y = 8

y = \dfrac{8}{3}

Hence, x = 0 and y = \dfrac{8}{3}.

If y = 0 then

2x + 3(0) = 8

2x = 8

x = 4

Hence, x = 4 and y = 0

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