Question

write a pair of integers whose produce is - 36 and whose difference is 15

Answer 1

Hey friend (^_^)

Here is your answer

Let the integers be x and x-15

ACCORDING TO QUESTION :

x(x-15)=-36

x²-15x+36=0

x²-12x-3x+36=0

x(x-12)-3(x-12)=0

(x-3)(x-12)=0

x=3 and x=12

WHEN x=3:

Two integers are x and x-15

x-15=3-15=-12

INTEGERS ARE =>3 and -12

WHEN x=12

Two integers are x and x-15

x-15=-3

INTEGERS ARE =>12 and -3

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HOPE THIS HELPS YOU

Answer 2

Hi ,

Let x , ( x - 15 ) are two Integers .

product of the Integers = - 36

x( x - 15 ) = -36

x² - 15x + 36 = 0

x² - 3x - 12x + 36 = 0

x( x - 3 ) - 12(x - 3 ) = 0

( x - 3 )( x - 12 ) = 0

Therefore ,

x - 3 = 0 or x - 12 = 0

x = 3 or x = 12

Now ,

Required two Integers are ,

i ) if x = 3

x - 15 = 3 - 15 = -12

( 3 , - 12 )

ii ) if x = 12 ,

x - 15 = 12 - 15 = -3

( 12 , - 3 )

I hope this helps you.

: )