Question

Write a polynomial whose zeroes are 2/3 and -1/3.​

Answer 1

Step-by-step explanation:

Polynomial

x² - ( 2/3 - 1/3 )x + (2/3)(-1/3) = 0

x² - x/3 - 2/9 = 0

9x² - 3x - 2 = 0

Answer 2

Step-by-step explanation:

k [x^2-(sum of zeroes)x+(product of zeroes)]

k [x^2-(-1/3+2/3)x+2/3*(-1/3)]

k[x^2 -1/3 x-2/9]= 9x^2- 3x -2