write a polynomial whose zeros are - 2 minus root 3 and 2 minus root 3
Answers
Answered by
11
Heya !!!
Sum of zeroes = (-2-✓3)+(2-✓3)
=> -✓6
Product of zeroes = ( - ✓3 - ✓2 ) ( -✓3 + 2 )
=> ( -✓3)² - (2)²
=> 3 - 4
=> -1
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes )X + Product of zeroes
=> X² - ( - ✓6 )X + (-1)
=> X² + ✓6X - 1
★ HOPE IT WILL HELP YOU ★
Sum of zeroes = (-2-✓3)+(2-✓3)
=> -✓6
Product of zeroes = ( - ✓3 - ✓2 ) ( -✓3 + 2 )
=> ( -✓3)² - (2)²
=> 3 - 4
=> -1
Therefore,
Required quadratic polynomial = X²-(Sum of zeroes )X + Product of zeroes
=> X² - ( - ✓6 )X + (-1)
=> X² + ✓6X - 1
★ HOPE IT WILL HELP YOU ★
Answered by
5
Sum of zeroes = - 2 - √3 + 2 - √3
Sum of zeroes = -√6
Product of zeroes = ( - 2 - √3)(2 - √3)
Product of zeroes = (- √3 - 2)(-√3 + 2)
Product of zeroes = (-√3)² - (2)²
Product of zeroes => 3 - 4 = -1
We know, polynomial = x² - (sum of zeroes)x + product of zeroes
So,
Polynomial = x² - (- √6x) - 1
Polynomial = x² + √6x - 1
Sum of zeroes = -√6
Product of zeroes = ( - 2 - √3)(2 - √3)
Product of zeroes = (- √3 - 2)(-√3 + 2)
Product of zeroes = (-√3)² - (2)²
Product of zeroes => 3 - 4 = -1
We know, polynomial = x² - (sum of zeroes)x + product of zeroes
So,
Polynomial = x² - (- √6x) - 1
Polynomial = x² + √6x - 1
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