Question

write a program to find the perimeter and area of a rectangle with length 6 cm and breadth 9 cm.

Answer 1

$\huge\mathbb{A~N~S~W~E~R}$
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$\small{\color{Red}{Perimeter~ of any~ polygon ~=~sum~ of~ all~ sides }}$

${ Perimeter~ of~rectangle= l+b+l+b}$

Rectangle have equal opposite sides.

$\large{\color{Red}{Perimeter~ of~rectangle= 2(l+b)} }$

Here ,

$l = 6 \: cm \\ \\ b = 9\: cm$

Use formula :-

$= 2(l + b ) \\ \\ = 2(9 + 6) \\ \\ = 2 \times 15 \\ \\ {\boxed{= 30 \: cm}}$

$\large{\color{Red}{ Area~ of~rectangle= l*b}}$

$= l \times b \\ \\ = 6 \times 9 \\ \\ ={\boxed{ 45 \: cm}^{2} }$

${\large\color{Red}{Answer~is~30~cm~and~{45cm}^{2}. }}$

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