write a pythagorean triplet whose smallest member is 16
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Answer:
16,63,65
Step-by-step explanation:
LET THE NUMBERS BE, m²-1, 2m , m²+1. NOW,
2m = 16 ⇒ m = 8..............NOW WE GOT m=8....WITH THAT,
m²-1 = 64-1 = 63
m²+1 = 64+1 = 65
∴ THE THREE TRIPLETS ARE ⇒ ( 16,63,65)
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