Math, asked by gagangupt09, 1 year ago

write a pythagorean triplet whose smallest member is 16

Answers

Answered by Anonymous
15

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Answered by vivekpnair11479
5

Answer:

16,63,65

Step-by-step explanation:

LET THE NUMBERS BE, m²-1, 2m , m²+1. NOW,

2m = 16 ⇒ m = 8..............NOW WE GOT m=8....WITH THAT,

m²-1 = 64-1 = 63

m²+1 = 64+1 = 65

∴ THE THREE TRIPLETS ARE ⇒ ( 16,63,65)

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