Question

write a Pythagorean triplet whose smallest member is 8​

Answer 1

Answer:

hii.

here is your answer.....

Smallest member of Pythagorean triplet =8

Now..

by using

2m,m^2 +1,m^2 -1

here,

2m =8

m= 4

m^2+1 = 4^2+1

= 16+1

=17..... second no. of Pythagorean triplet.

now,

using,

m^2-1 = 4^2-1

= 16-1

=15....third no.....

Pythagorean triplet = 8,17,15.

... ans....

now,

thanks.....

mark my answer brainliest plzz...

and

Answer 2

$we \:can \: get \: pythagorean \: triplet \:by \: using \: general \: form \: 2m \: m {}^{2} - 1 \: m {}^{2} + 1. \\ \\ lets \: us \: first \: take \: \: \: m {}^{2} - 1 = 8 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: m {}^{2} = 8 + 1 = 9 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: m = 3 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2m = 6 \: and \: m {}^{2} + 1 = 10 \\ \\ te \: triplet \: is \: thus \: 6 \: 8 \: 10.but \: 8 \: is \: smallest \: member \: of \: this. \\ \\ so \: let \: us \: try \: \: \: \: \: \: 2m = 8 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: m = 4 \\ \\ \: \: \: m {}^{2} - 1 = 16 - 1 = 15 \\ \\ m {}^{2} + 1 = 1 + 1 = 17 \\ \\ \\ \\ \\ the \: triplet \: is \: 8 </strong><strong>\: 15 </strong><strong>\: 17 \: with \: 8 \: as \: the \: smallest \: member.$