Write a quadratic polynomial, sum of whose zeroes is 3 and product is -18.
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Answered by
2
x²-3x-18 is the answer.
Sum of zeroes = -b/a = 3
Product of zeroes = c/a = -18
Hope this helps...
Answered by
3
Let α and β are the roots of given Quadratic polynomial.
Given:
α+β = 3 , αβ = -18
Quadratic polynomial :- x² - (α+β)x + (αβ)
∴ Polynomial is x² − 3x - 18
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