Question

write a relation for the electrostatic force between two point charges placed in a dielectric medium

Answer 1

let the point charges be q1 and q2, and the distance between them be d.
Now, let the permeability of the medium be €r
Thus, from coulomb law, the expression is,

F = q1*q2/(4π€r*d^2)

Answer 2

$F=\dfrac{1}{4\pi \epsilon_o\epsilon_r}\dfrac{q_1q_2}{r^2}$

Explanation:

The electrostatic force exists between two charged particles. It is given by the formula as follows :

$F=\dfrac{kq_1q_2}{r^2}$

Where

r is the distance between charges

k is the electric constant

$k=\dfrac{1}{4\pi \epsilon_o}$

$\epsilon_o$ is the permitivity of free space.

For any medium,

$k=\dfrac{1}{4\pi \epsilon_o\epsilon_r}$

So,

$F=\dfrac{1}{4\pi \epsilon_o\epsilon_r}\dfrac{q_1q_2}{r^2}$

Hence, this is the required solution.

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