Physics, asked by Anonymous, 8 months ago

Write an activity to show that liquid can exert pressure on an object which is proportional to height of liquid column above the object.

Answers

Answered by anishssgjpaxp0c
2

Answer:

The pressure difference can be seen in a simple experiment. Fill up a bottle with water and take a pin to poke holes in the bottle. Now poke a hole on the top of the bottle near the surface of the water. The water dribbles out slowly from this hole. Now start moving down and making holes. As you move down, the speed and the distance travelled by the stream of water coming out of the hole increases

The speed and the distance of the outlet are maximum close to the bottom. The water pours out of the hole due to the pressure acting on the container by water in all sides. The pressure acting on the water decides the speed and the distance of the stream and at a particular height it is constant, as in if multiple holes are made in the bottle at the same height, then the flow of water from all the holes will be equal

Observation:

Also, another curious observation here is that pressure acting on a layer of fluid in the bottom is proportional to the product of the height of fluid above it to its density. The hydrostatic pressure is caused in fluids mainly because of the gravitational force acting on every layer of the fluid.

This property of fluid pressure means that the pressure at the deep portions of the oceans are truly enormous and they are. With every 10 meters, you go into the ocean, an extra 1 kilogram of pressure is added per square centimetre of your body. After a certain depth, the pressure becomes high enough to crush a human being if they are not wearing special equipment. These properties hold true for gases as well which we will explore in our article on the Atmospheric pressure.

Answered by vichunambiar2003
0

Answer

Explanation:

dip a cylinder in a beaker pressure is applied from both sides so the difference between them is :

the total force is( P1A-P2A)=mg

here A(P1-P2)=mg

P1-P2=mg/A

m=(rho)V     take rho=r

P1-P2=rVg/A                   V=volume

V/A=l

P1-P2=rlg

so directly proportional to l (length)

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