Question

Write an equation in standard form of the circle. (x-3)^2+(y+5)^2=64

Answer 1

given that (x-3)² +(y+5)² = 64
standard form of circle =( x-h)+ (y- k) = r ²
where r is radius of circle and h n k is it
now, ( x-3)² +( y +(-5))² = 8²
here center is (3,-5) n radius = 8

Answer 2

Answer:

The standard form of the circle is $(x-3)^2+(y+5)^2=8^2$.

Step-by-step explanation:

The given equation is

$(x-3)^2+(y+5)^2=64$

The standard form of the circle is,

$(x-h)^2+(y-k)^2=r^2$

where, (h,k) is the center and r is the radius.

The given equation can be written as

$(x-3)^2+(y+5)^2=8^2$

The circle of circle is (3,-5) and radius is 8.

Therefore the standard form of the circle is $(x-3)^2+(y+5)^2=8^2$.